If anyone can help with these measurements, something just seems off, I'm
terrible at geometry, but can measure and cut just fine.
I'm wanting to build a corner cabinet for my tv and related equipment. The
design size is limited on one side to 34" because of a door jamb. The shape
I've come up with is 5 sided-essentially the same as a profile of a diamond
from a ring-not a pentagon. Measurements of 22" for the front (tv screen
edge), 12" each side, then 34" for each of the back sides. I've just cut
out graph paper, one square to one inch to fit these measurements. The TV
itself is box shaped, narrowing slightly towards the back. 25" across the
front screen edge, 19" deep, and 19" wide at the back. I've also cut the
graph paper to fit those measurements. The tv paper fits well inside the
cabinet paper, but it doesn't seem like it should. Given that the cabinet
paper front edge is only 22 squares (cut on the diagonal) and tv paper is
25 squares wide, how is this possible. Have I measured wrong, is it a
matter of perception, something else? I don't want to buy and cut wood if
this just isn't going to work.
Thanks!
--
Melissa
[email protected]
Melissa wrote:
>
> If anyone can help with these measurements, something just seems off, I'm
> terrible at geometry, but can measure and cut just fine.
> I've come up with is 5 sided-essentially the same as a profile of a diamond
> from a ring-not a pentagon.
A pentagon is a Five Sided figure, a diamond can be any shape?????
jim wrote:
>
> Melissa wrote:
> >
> > If anyone can help with these measurements, something just seems off, I'm
> > terrible at geometry, but can measure and cut just fine.
> > I've come up with is 5 sided-essentially the same as a profile of a diamond
> > from a ring-not a pentagon.
> A pentagon is a Five Sided figure, a diamond can be any shape?????
She said profile. most stones are cut with a flat top, a
short bevel about 30 degrees down and then the bevel to a
point at the bottom of the stone. In profile that is a
pentagon.
In rec.woodworking
"Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote:
>If anyone can help with these measurements, something just seems off, I'm
>terrible at geometry, but can measure and cut just fine.
>
>I'm wanting to build a corner cabinet for my tv and related equipment. The
>design size is limited on one side to 34" because of a door jamb. The shape
>I've come up with is 5 sided-essentially the same as a profile of a diamond
>from a ring-not a pentagon. Measurements of 22" for the front (tv screen
>edge), 12" each side, then 34" for each of the back sides. I've just cut
>out graph paper, one square to one inch to fit these measurements. The TV
>itself is box shaped, narrowing slightly towards the back. 25" across the
>front screen edge, 19" deep, and 19" wide at the back. I've also cut the
>graph paper to fit those measurements. The tv paper fits well inside the
>cabinet paper, but it doesn't seem like it should. Given that the cabinet
>paper front edge is only 22 squares (cut on the diagonal) and tv paper is
>25 squares wide, how is this possible. Have I measured wrong, is it a
>matter of perception, something else? I don't want to buy and cut wood if
>this just isn't going to work.
I'm not able to reproduce a design like that in AutoCAD. Are the 2 34"
pieces at a right angle? That is what I assumed since it is in a corner.
If they are, the geometry doesn't work. The 22" front will never intersect
12" sides.
In rec.woodworking
"Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote:
>I'm wanting to build a corner cabinet for my tv and related equipment. The
>design size is limited on one side to 34" because of a door jamb. The shape
>I've come up with is 5 sided-essentially the same as a profile of a diamond
>from a ring-not a pentagon. Measurements of 22" for the front (tv screen
>edge), 12" each side, then 34" for each of the back sides. I've just cut
>out graph paper, one square to one inch to fit these measurements. The TV
>itself is box shaped, narrowing slightly towards the back. 25" across the
>front screen edge, 19" deep, and 19" wide at the back. I've also cut the
>graph paper to fit those measurements. The tv paper fits well inside the
>cabinet paper, but it doesn't seem like it should. Given that the cabinet
>paper front edge is only 22 squares (cut on the diagonal) and tv paper is
>25 squares wide, how is this possible. Have I measured wrong, is it a
>matter of perception, something else? I don't want to buy and cut wood if
>this just isn't going to work.
I've tried to draw this in AutoCAD and I get the idea but it won't work
with the measurements you gave me unless the 2 34" sides aren't
perpendicular. Are they? If so, the 22" will never meet the 12" sides.
In alt.home.repair
Bay Area Dave <[email protected]> wrote:
>talk about overkill! her question has already been answered, without
>the need for Autocad...sigh...
Actually, those weren't supposed to be sent because I'd seen it was already
answered. As for AutoCAD, I do everything in AutoCAD and hardly consider
it overkill. I drew it up in about 3 minutes, much easier than sketching
it on paper.
In alt.home.repair
Bay Area Dave <[email protected]> wrote:
>I'm not saying anything's wrong with using Autocad, Bruce; just that the
>OP's question was of a basic nature, needing a simple answer regarding
>diagonals.
Dave,
I drew it out to determine what her problem was. I had no idea she was
equating the hypotenuse of a square with the side of a square because I
found her description hard to follow. I'm much more visual. Once I saw
the picture, the light went on.
"Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote in message news:<MDFIb.159931$%[email protected]>...
> If anyone can help with these measurements, something just seems off, I'm
> terrible at geometry, but can measure and cut just fine.
>
> I'm wanting to build a corner cabinet for my tv and related equipment. The
> design size is limited on one side to 34" because of a door jamb. The shape
> I've come up with is 5 sided-essentially the same as a profile of a diamond
> from a ring-not a pentagon. Measurements of 22" for the front (tv screen
> edge), 12" each side, then 34" for each of the back sides. I've just cut
> out graph paper, one square to one inch to fit these measurements. The TV
> itself is box shaped, narrowing slightly towards the back. 25" across the
> front screen edge, 19" deep, and 19" wide at the back. I've also cut the
> graph paper to fit those measurements. The tv paper fits well inside the
> cabinet paper, but it doesn't seem like it should. Given that the cabinet
> paper front edge is only 22 squares (cut on the diagonal) and tv paper is
> 25 squares wide, how is this possible. Have I measured wrong, is it a
> matter of perception, something else? I don't want to buy and cut wood if
> this just isn't going to work.
>
> Thanks!
The diagonal front face of the box is 31.11"
Tom Baker
"Jim Wilson" <[email protected]> wrote in message
news:[email protected]...
> TinWoodsmn wrote...
> > One last try...
>
> (g)
>
> > Start with a square 34" on each side. Choose one corner and measure
along
> > the side 16" and make a mark. From the same corner measure 16" along the
> > other side and mark it. Connect the two marks forming a 'diagonal' line.
Its
> > length is 22 5/8". This should satisfy all the conditions set down by
the
> > OP. Does this solve her problem?
>
> Well, the problem was that the 22" she gave was wrong. She actually had
> counted 22 diagonals, but they are 1.414" each, so as Tom noted,
>
> > > The diagonal front face of the box is 31.11"
>
> Cheers!
>
> Jim
It isn't the diagonal of 31.11" which is the governing number, it's the TV.
To enclose it we need a trapezoid with 25" (front of TV) and 19" (rear of
TV) parallel sides with a height of at least 19" (length of TV). In
addition, the overall container can have one side 34" long maximum (door
jamb). Again start with a 34" square. Proceed as in my last post, except
change the 16" dimension to 17 3/4". When completed, the box has a 25" wide
face for the TV screen, two rear adjacent 34" sides and will contain a TV
with a 25" wide face, 19" wide rear and about 26" long.
TW
talk about overkill! her question has already been answered, without
the need for Autocad...sigh...
dave
Bruce wrote:
> In rec.woodworking
> "Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote:
>
>
>>I'm wanting to build a corner cabinet for my tv and related equipment. The
>>design size is limited on one side to 34" because of a door jamb. The shape
>>I've come up with is 5 sided-essentially the same as a profile of a diamond
>
>>from a ring-not a pentagon. Measurements of 22" for the front (tv screen
>
>>edge), 12" each side, then 34" for each of the back sides. I've just cut
>>out graph paper, one square to one inch to fit these measurements. The TV
>>itself is box shaped, narrowing slightly towards the back. 25" across the
>>front screen edge, 19" deep, and 19" wide at the back. I've also cut the
>>graph paper to fit those measurements. The tv paper fits well inside the
>>cabinet paper, but it doesn't seem like it should. Given that the cabinet
>>paper front edge is only 22 squares (cut on the diagonal) and tv paper is
>>25 squares wide, how is this possible. Have I measured wrong, is it a
>>matter of perception, something else? I don't want to buy and cut wood if
>>this just isn't going to work.
>
>
> I've tried to draw this in AutoCAD and I get the idea but it won't work
> with the measurements you gave me unless the 2 34" sides aren't
> perpendicular. Are they? If so, the 22" will never meet the 12" sides.
>
"Jim Wilson" <[email protected]> wrote in message
news:[email protected]...
> I'm not sure you have the sizes you think you do. 22 diagonals would be
> just under 31-1/8". A square's diagonal is about 1.414 times the length
> of a side. That would account for your TV model fitting in the space, but
> then you'd have the wrong measurements for the plan view of the cabinet.
> Are all the angles right angles? If so, then all your measurements given
> above work except the front, which is actually 31.110".
>
> Cheers!
>
> Jim
My information was off. I gave measurements for all but the front edge,
that I gave in squares. I made the other measurements on the wall itself,
but couldn't make the diagonal measurement (couldn't get the m. tape to
steady enough for that), so was going on the incorrect assumption that the
diagonal of the square was the same as the length of a side. Corrected now,
thanks!
--
Melissa
sounds like a simple math problem. YOU and the rest of us that have
half a brain know that the diagonal of a square is longer than a side...
think "a" squared plus "b" squared equals "c" squared...
a and b are sides and c is the diagonal. I'll let YOU do the rest.
dave
Melissa wrote:
> If anyone can help with these measurements, something just seems off, I'm
> terrible at geometry, but can measure and cut just fine.
>
> I'm wanting to build a corner cabinet for my tv and related equipment. The
> design size is limited on one side to 34" because of a door jamb. The shape
> I've come up with is 5 sided-essentially the same as a profile of a diamond
> from a ring-not a pentagon. Measurements of 22" for the front (tv screen
> edge), 12" each side, then 34" for each of the back sides. I've just cut
> out graph paper, one square to one inch to fit these measurements. The TV
> itself is box shaped, narrowing slightly towards the back. 25" across the
> front screen edge, 19" deep, and 19" wide at the back. I've also cut the
> graph paper to fit those measurements. The tv paper fits well inside the
> cabinet paper, but it doesn't seem like it should. Given that the cabinet
> paper front edge is only 22 squares (cut on the diagonal) and tv paper is
> 25 squares wide, how is this possible. Have I measured wrong, is it a
> matter of perception, something else? I don't want to buy and cut wood if
> this just isn't going to work.
>
> Thanks!
>
Melissa wrote...
> If anyone can help with these measurements, something just seems off, I'm
> terrible at geometry, but can measure and cut just fine.
>
> I'm wanting to build a corner cabinet for my tv and related equipment. The
> design size is limited on one side to 34" because of a door jamb. The shape
> I've come up with is 5 sided-essentially the same as a profile of a diamond
> from a ring-not a pentagon. Measurements of 22" for the front (tv screen
> edge), 12" each side, then 34" for each of the back sides. I've just cut
> out graph paper, one square to one inch to fit these measurements. The TV
> itself is box shaped, narrowing slightly towards the back. 25" across the
> front screen edge, 19" deep, and 19" wide at the back. I've also cut the
> graph paper to fit those measurements. The tv paper fits well inside the
> cabinet paper, but it doesn't seem like it should. Given that the cabinet
> paper front edge is only 22 squares (cut on the diagonal) and tv paper is
> 25 squares wide, how is this possible. Have I measured wrong, is it a
> matter of perception, something else? I don't want to buy and cut wood if
> this just isn't going to work.
I'm not sure you have the sizes you think you do. 22 diagonals would be
just under 31-1/8". A square's diagonal is about 1.414 times the length
of a side. That would account for your TV model fitting in the space, but
then you'd have the wrong measurements for the plan view of the cabinet.
Are all the angles right angles? If so, then all your measurements given
above work except the front, which is actually 31.110".
Cheers!
Jim
TinWoodsmn wrote...
> Draw two 34" lines at 90 deg to each other. At the end of these lines draw a
> 12" radius circle. Connect the circle centers. Cut a piece of graph paper to
> 22" and carefully place it between the circles so that simultaneously the
> ends touch the circles and the paper is parallel to the line joining the
> centers.
Except in this case, a 22" segment cannot touch both circles, because
they are over 24" apart at the closest.
Jim
TinWoodsmn wrote...
> One last try...
(g)
> Start with a square 34" on each side. Choose one corner and measure along
> the side 16" and make a mark. From the same corner measure 16" along the
> other side and mark it. Connect the two marks forming a 'diagonal' line. Its
> length is 22 5/8". This should satisfy all the conditions set down by the
> OP. Does this solve her problem?
Well, the problem was that the 22" she gave was wrong. She actually had
counted 22 diagonals, but they are 1.414" each, so as Tom noted,
> > The diagonal front face of the box is 31.11"
Cheers!
Jim
TinWoodsmn wrote...
> It isn't the diagonal of 31.11" which is the governing number, it's the TV.
But she wasn't trying to design the cabinet anymore by then. She already
had the shape she liked. She was wondering how the TV was able to fit in
the scale mock-up when the front dimension of the cabinet seemed smaller
than the TV.
Jim
"Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote in message
news:H8GIb.160203$%[email protected]...
> "Jim Wilson" <[email protected]> wrote in message
> news:[email protected]...
>
> > I'm not sure you have the sizes you think you do. 22 diagonals would be
> > just under 31-1/8". A square's diagonal is about 1.414 times the length
> > of a side. That would account for your TV model fitting in the space,
but
> > then you'd have the wrong measurements for the plan view of the cabinet.
> > Are all the angles right angles? If so, then all your measurements given
> > above work except the front, which is actually 31.110".
> >
> > Cheers!
> >
> > Jim
>
> My information was off. I gave measurements for all but the front edge,
> that I gave in squares. I made the other measurements on the wall itself,
> but couldn't make the diagonal measurement (couldn't get the m. tape to
> steady enough for that), so was going on the incorrect assumption that the
> diagonal of the square was the same as the length of a side. Corrected
now,
> thanks!
>
> --
> Melissa
>
Your mistake is assuming the diagonals of the graph paper are 1". They are
actually 1.414".
Draw two 34" lines at 90 deg to each other. At the end of these lines draw a
12" radius circle. Connect the circle centers. Cut a piece of graph paper to
22" and carefully place it between the circles so that simultaneously the
ends touch the circles and the paper is parallel to the line joining the
centers. Mark on the circles where the graph paper has touched. Draw lines
from these points to the circle centers. You have your five sided diamond.
Angles can be read with a protractor.
Good luck.
TW
I'm not saying anything's wrong with using Autocad, Bruce; just that the
OP's question was of a basic nature, needing a simple answer regarding
diagonals.
dave
Bruce wrote:
> In alt.home.repair
> Bay Area Dave <[email protected]> wrote:
>
>
>>talk about overkill! her question has already been answered, without
>>the need for Autocad...sigh...
>
>
> Actually, those weren't supposed to be sent because I'd seen it was already
> answered. As for AutoCAD, I do everything in AutoCAD and hardly consider
> it overkill. I drew it up in about 3 minutes, much easier than sketching
> it on paper.
>
Cool!
dave
Melissa wrote:
> Thanks Dave, that's exactly the problem. As I said, I'm terrible at
> geometry, so bad that I didn't realize the diagonal was longer than the
> sides. I guess my half brain isn't the half that can handle that. :) All
> set now, just needed a bit of reassurance that the tv would indeed fit.
> Thanks!
>
"Jim Wilson" <[email protected]> wrote in message
news:[email protected]...
> TinWoodsmn wrote...
> > Draw two 34" lines at 90 deg to each other. At the end of these lines
draw a
> > 12" radius circle. Connect the circle centers. Cut a piece of graph
paper to
> > 22" and carefully place it between the circles so that simultaneously
the
> > ends touch the circles and the paper is parallel to the line joining the
> > centers.
>
> Except in this case, a 22" segment cannot touch both circles, because
> they are over 24" apart at the closest.
>
> Jim
Jim, you're absolutely right. I should have checked my work more closely
before sending a non solution.
Happy New Year to all.
TW
"Tom Baker" <[email protected]> wrote in message
news:[email protected]...
> "Melissa" <melsmail(yourshoes)@tampabay.rr.com> wrote in message
news:<MDFIb.159931$%[email protected]>...
> > If anyone can help with these measurements, something just seems off,
I'm
> > terrible at geometry, but can measure and cut just fine.
> >
> > I'm wanting to build a corner cabinet for my tv and related equipment.
The
> > design size is limited on one side to 34" because of a door jamb. The
shape
> > I've come up with is 5 sided-essentially the same as a profile of a
diamond
> > from a ring-not a pentagon. Measurements of 22" for the front (tv
screen
> > edge), 12" each side, then 34" for each of the back sides. I've just
cut
> > out graph paper, one square to one inch to fit these measurements. The
TV
> > itself is box shaped, narrowing slightly towards the back. 25" across
the
> > front screen edge, 19" deep, and 19" wide at the back. I've also cut
the
> > graph paper to fit those measurements. The tv paper fits well inside
the
> > cabinet paper, but it doesn't seem like it should. Given that the
cabinet
> > paper front edge is only 22 squares (cut on the diagonal) and tv paper
is
> > 25 squares wide, how is this possible. Have I measured wrong, is it a
> > matter of perception, something else? I don't want to buy and cut wood
if
> > this just isn't going to work.
> >
> > Thanks!
>
> The diagonal front face of the box is 31.11"
>
> Tom Baker
One last try...
Start with a square 34" on each side. Choose one corner and measure along
the side 16" and make a mark. From the same corner measure 16" along the
other side and mark it. Connect the two marks forming a 'diagonal' line. Its
length is 22 5/8". This should satisfy all the conditions set down by the
OP. Does this solve her problem?
TW